TRAPLOOP | Editorial by Uvaish

TRAPLOOP | Editorial by Uvaish_Zafri

**Problem Statement:**
>Sumit is fond of various shapes but particularly he likes trapezium. He came across a special trapezium in which non - parallel sides are equal in length and named it as isosceles trapezium. 
>He decided to tell about this fact to his friend Dhananjay.Dhananjay thought of making a circular closed loop by joining the edges of this isosceles trapezium.
> So he asked Sumit to calculate the total number of isosceles trapezuims they will require to form a closed loop. As Sumit is busy in preparation of New Year, he asks for your help!
>You are given a base angle x of the isosceles trapezuim click here. Your task is to calculate the total number of isosceles trapeziums required to form a closed loop.
so,let's consider some examples for better understanding

Sample Input:
**1
80**
Sample Output:
**18**

this question is simply just a mathematical problem. where we just need to print the  total number of isosceles triangles required to form a closed loop.

so, lets now code this in CPP :)

```
#include<bits/stdc++.h>
#define ll long long 
using namespace std;

int main()
{
    
    int t;
    cin>>t;
    while(t--)
    {
        int x;
        cin>>x;
        int res;
        res=360/(180-2*x);  //direct formula
        
        cout<<res<<endl;
    }
    return 0;
}
```

TRAPLOOP | Editorial by Uvaish_Zafri

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