INF1908 | Editorial by Uvaish

INF1908 | Editorial by Uvaish_Zafri

**Problem:**
>"The things I do for love" - Jaime Lannister
>Ser Jaime Lannister was the best swordsman in the whole of Westeros. But after Locke cut off his right hand, he could no longer fight. He is now trying to learn addition of numbers.
>He only knows how to add 1 to each number. He does it correctly except when the last digit is 9, he changes it to 0. Given a number N , you have to add 1 to it K times.
>Output the final answer Ser Jaime will get.

Sample Input:
**1
58 24**
Sample Output:
**52**

as the concerned person converts 9 to 0 after addition leaving all other digits as it is. so, we just need to work on the last digit of the given number and that number will only be affected by last digit of K eventually.

ex: N=58 K=24 
1.subtract 8 from 58 making it 50.
2.find value of (8+4)%10 which is 2 in this case.
3.add this value to N making 50+2=52.

Now, lets code it in C++ :)

```
#include<bits/stdc++.h>
#define ll long long
using namespace std;

main() {
    ll test;
	cin>>test;
	while(test--)
     {
	   ll n,k;
	   cin>>n>>k;
       ll temp=n%10;
       n-=temp;  //first step
       ll temp2=(temp+k%10)%10; //second step
       cout<<n+temp2<<endl; //third step
	 }
	return 0;
}
}
```

INF1908 | Editorial by Uvaish_Zafri

Download submission

All caught up!

View submission

Is your resume even shortlisted?