Balanced Strings | Editorial by shivamjaiswal64

In this question,
* we have to count the number of character of a to z and store in array c.
* Initialise , another array c2 which contains all elements equal to the no. of first element in array c.
* If both array are equal then print "Yes" otherwise "No".

``` 
import java.util.*;
class TestClass{
    public static void main(String args[] ) throws Exception {
        Scanner s = new Scanner(System.in);
        int t=s.nextInt();
        while(t-->0){
            String str=s.next();
            int len=str.length();
            int c[]=new int[26];
            for(int i=0;i<len;i++){
                char ch=str.charAt(i);
                int n=ch-97;
                c[n]++;
            }
            int c2[]=new int[26];
            Arrays.fill(c2,c[0]);
            if(Arrays.equals(c,c2))
            System.out.println("Yes");
            else
            System.out.println("No");
        }
    }
}

```
Editorial By: [Shivam Jaiswal](https://www.stopstalk.com/user/profile/shivamjaiswal64)

Balanced Strings | Editorial by shivamjaiswal64

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