B. Go to Jail | Editorial by harshitgupta

### Editorial

This is an editorial for the problem [Go To Jail](https://atcoder.jp/contests/abc179/tasks/abc179_b), from AtCoder.

The problem is simple, and just requires to check for three consecutive pairs of numbers that have equal (or same) number. If there does exist three pairs _consecutively_, the output will be a 'Yes' (without quotes), else the output will be 'No' (without quotes). Certainly, if there's any one such pair, the answer is deduced and there's no need to check further pairs.

The straightforward, as stated, code (in ***Python 3***) for the problem is as follows: 
```
count = 0          # This will keep a count of consecutives
for dice_roll in range(int(input())):
    count += 1
    dice_a, dice_b = map(int, input().split())
    if dice_a != dice_b: count=0        # Resetting the consecutive count whenever the streak breaks
    if count>2:
        print("Yes")
        exit()     # break, alternatively
else:print("No")
```

Any further comments/suggestions? Feel free to start a discussion!

B. Go to Jail | Editorial by harshitgupta

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